A $6.0\,volt$ battery is connected to two light bulbs as shown in figure. Light bulb $1$ has resistance $3\,ohm$ while light bulb $2$ has resistance $6\,ohm.$ Battery has negligible internal resistance. Which bulb will glow brighter?
ABulb $1$ will glow more first and then its brightness will become less than bulb $2$
BBulb $1$
CBulb $2$
D
Both glow equally
AIEEE 2012, Diffcult
Download our app for free and get started
BBulb $1$
b Total resistance $=\frac{6 \times 3}{6+3}=2 \,\Omega$
Current in circuit $=\frac{6}{2}=3 \,\mathrm{A}$
Therefore current through bulb $1$ is $2 \,A$ and bulb $2$ is $1\, A .$ So bulb $1$ will glow more
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Two bulbs of $100\, W$ and $200\, W$ working at $220$ $volt$ are joined in series with $220$ $volt$ supply. Total power consumed will be approximately ........... $watt$
Each element in the finite chain of resistors shown in the figure is $1\,\Omega $. A current of $1\, A$ flows through the final element. Then what is the potential difference $V$ across input terminals of the chain ............... $\mathrm{volt}$
A potential divider is used to give outputs of $4\, V$ and $8\, V$ from a $12\, V$ source. Which combination of resistances, $(R_1, R_2, R_3)$ gives the correct voltages ? $R_1 : R_2 : R_3$
In a Wheatstone’s bridge all the four arms have equal resistance $R$. If the resistance of the galvanometer arm is also $R$, the equivalent resistance of the combination as seen by the battery is