Question
A 80m by 64m rectangular lawn has two roads, each 5m wide, running through its middle, one parallel to its length and the other parallel to its breadth. Find the cost of gravelling the roads at ₹ 40 per $m^2.$
✓
Answer
Area of the road $A B C D=80 \times 5=400 m^2$
Area of the road $EFGH =64 \times 5=320 m^2$
Area of the road $PQRS =5 \times 5=25 m^2$
Road PQRS is common to both the roads $A B C D$ and $E F G H$.
$\therefore \text { Area of the road to be gravelled }$
$=\text { Area of the road } A B C D+\text { Area of the road EFGH - Area of the road PQRS }$
$=(400+320-25) m^2$
$=695 m^2$
Now, cost of gravelling the roads $=₹ 40$ per $m ^2$
$\therefore$ Cost of gravelling $695 m^2$ road $=₹ 40 \times 695=₹ 27800$.
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