$A$ and $B$ are two students. Their chances of solving a problem correctly are $\frac{1}{3}$ and $\frac{1}{4}$ respectively. If the probability of their making common error is $\frac{1}{20}$ and they obtain the same answer, then the probability of their answer to be correct is.
  • A$\frac{10}{13}$
  • B$\frac{13}{120}$
  • C$\frac{1}{40}$
  • D$\frac{1}{12}$
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