MCQ
$A$ and $B$ in the following reactions are
- ✓
- B
- C
- D$A = RR'C{H_2}CN,B = NaOH$
✓
Answer
Correct option: A.
a
(a) $R - CO - R\,'\xrightarrow{{HCN}}$ - $\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,OH} \\
|
\end{array}} \\
{R - C - R'} \\
{|\,\,} \\
{\,\,\,\,CN}
\end{array}\xrightarrow{{LiAl{H_4}}}$ $\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,OH}\,\, \\
|
\end{array}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{R - C - C{H_2}N{H_2}} \\
\,\,\, {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,\,R'\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
(a) $R - CO - R\,'\xrightarrow{{HCN}}$ - $\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,OH} \\
|
\end{array}} \\
{R - C - R'} \\
{|\,\,} \\
{\,\,\,\,CN}
\end{array}\xrightarrow{{LiAl{H_4}}}$ $\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,OH}\,\, \\
|
\end{array}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{R - C - C{H_2}N{H_2}} \\
\,\,\, {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,\,R'\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
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