A ball of relative density $0.8$ falls into water from a height of $2$ $m$. The depth to which the ball will sink is ........ $ m$ (neglect viscous forces) :
Medium
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Buoyancy force $=(d v) g$
$m=d^{\prime} V$
acceleration$=\frac{\text {net force}}{m}=\frac{d V g}{d^{\prime} V}$
$\Rightarrow \frac{d \times g}{d^{\prime}}=\frac{10}{0.8}=12.5 \mathrm{m} / \mathrm{s}^{2}$
depth it gets sinked down$:$
$\Rightarrow(2 g \times 2)=0^{2}+2 \times g \times s$
$s=8 m$
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