MCQ
A ball projected from ground vertically upward is at same height at time $t_1$ and $t_2$. The speed of projection of ball is [Neglect the effect of air resistance]
- A$g\left[t_2-t_1\right]$
- ✓$\frac{g\left[t_1+t_2\right]}{2}$
- C$\frac{g\left[t_2-t_1\right]}{2}$
- D$g\left[t_1+t_2\right]$


