Question
A ball thrown up vertically returns to the thrower after 6s. Find the maximum height it reaches.

Answer

Let the maximum height attained by the ball be h.
Initial velocity during the upward journey, u = 29.4m s-1
Final velocity, v = 0
Acceleration due to gravity, g = -9.8m s-2
From the equation of motion, s = ut + 1/2 at2
h = 29.4 × 3 + 1/2 × -9.8 × (3)2 = 44.1m

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