Gujarat BoardEnglish MediumSTD 9ScienceGravitation3 Marks
Question
A ball thrown up vertically returns to the thrower after $6s$. Find the maximum height it reaches.
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Answer
Let the maximum height attained by the ball be h . Initial velocity during the upward journey, $\mathrm{u}=29.4 \mathrm{~m} \mathrm{~s}^{-1}$ Final velocity, $v=0$ Acceleration due to gravity, $g=-9.8 \mathrm{~m} \mathrm{~s}^{-2}$ From the equation of motion, $s=u t+1 / 2 \mathrm{at}^2 \mathrm{~h}=29.4 \times 3$ $+1 / 2 \times-9.8 \times(3)^2=44.1 \mathrm{~m}$
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