A ball thrown vertically upwards falls back on the ground after 6… - Vidyadip

MCQ

A ball thrown vertically upwards falls back on the ground after $6$ second. Assuming that the equation of motion is of the form $s = ut - 4.9{t^2}$, where s is in metre and $t$ is in second, find the velocity at $t = 0$ .......... $m/s$.

A
$0$
B
$1$
✓
$29.4$
D
None of these

✓

Answer

Correct option: C.

$29.4$

c
(c) Velocity of ball $(v) =\frac{{ds}}{{dt}} = $$u - 9.8\,t$

Here terminal velocity $v = 0$ and $t = 3\,sec$

$u = 9.8(3) = 29.4 \,m/sec$.

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