A block of ice floats on a liquid of density $1.2$ in a beaker then level of liquid when ice completely melt
IIT 1994, Medium
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(b)The volume of liquid displaced by floating ice ${V_D} = \frac{M}{{{\sigma _L}}}$
Volume of water formed by melting ice, ${V_F} = \frac{M}{{{\sigma _W}}}$
If ${\sigma _1} > {\sigma _W},$then, $\frac{M}{{{\sigma _L}}} < \frac{M}{{{\sigma _W}}}$i.e. ${V_D} < {V_F}$
i.e. volume of liquid displaced by floating ice will be lesser than water formed and so the level if liquid will rise.
Volume of water formed by melting ice, ${V_F} = \frac{M}{{{\sigma _W}}}$
If ${\sigma _1} > {\sigma _W},$then, $\frac{M}{{{\sigma _L}}} < \frac{M}{{{\sigma _W}}}$i.e. ${V_D} < {V_F}$
i.e. volume of liquid displaced by floating ice will be lesser than water formed and so the level if liquid will rise.
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