A block of steel of size $ 5 cm × 5 cm × 5 cm $ is weighed in water. If the relative density of steel is $7,$ its apparent weight is
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(a) Apparent weight = $V(\rho - \sigma )g$
= $5 \times 5 \times 5(7 - 1)g$= $6 \times 5 \times 5 \times 5\;gf$
= $5 \times 5 \times 5(7 - 1)g$= $6 \times 5 \times 5 \times 5\;gf$
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