MCQ
A blue colouration is not obtained when
- AAmmonium hydroxide dissolves in copper sulphate
- ✓Copper sulphate solution reacts with ${K_4}[Fe{(CN)_6}]$
- CFerric chloride reacts with sodium ferrocyanide
- DAnhydrous $CuS{O_4}$ is dissolved in water
$4N{H_4}OH + CuS{O_4} \to \mathop {[Cu{{(N{H_3})}_4}]}\limits_{{\rm{Deep}}\,{\rm{blue}}} \,S{O_4} + 4{H_2}O$
$\mathop {CuS{O_4}}\limits_{{\rm{Anhydrous}}} + 5{H_2}O \to \mathop {CuS{O_4}}\limits_{{\rm{Blue}}} .5{H_2}O$
$4FeC{{l}_{3}}+3N{{a}_{4}}[Fe{{(CN)}_{6}}]\to \underset{\begin{smallmatrix}
\text{Ferric}\,\text{ferrocyanide} \\
\,\,\,\,\,\text{(Prussian}\,\text{blue)}
\end{smallmatrix}}{\mathop{F{{e}_{4}}[Fe{{(CN)}_{6}}]}}\,+12NaCl$
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$CH_2OH-CHOH-CH_2OH$ $\xrightarrow{{KHS{O_4}/\Delta }}(X)\mathop {\xrightarrow{{{{({C_2}{H_5}O)}_3}Al}}}\limits_\Delta (Y)$
$(Y)$ will be:
(Round off to the Nearest Integer).
[Given : Henry's law constant $= K _{ H }=8.0 \times 10^{4} kPa$ for $O _{2}$ Density of water with dissolved oxygen $=1.0\, kg\, dm ^{-3}$ ]
$\begin{matrix}
O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}-C-OH+C{{H}_{3}}-OH\overset{cat.}{\longleftrightarrow} \\
\end{matrix}\begin{matrix}
O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}-C-O-C{{H}_{3}}+{{H}_{2}}O \\
\end{matrix}$
$(I)$ $\phi -CH_3$
$(II)$ $\phi -CH_2-CH_3$
$(III)$ $\phi -CH(CH_3)_2$
$(IV)$ $\phi-C(CH_3)_3$
towards electrophilic substitution will be - [where $\phi =C_6H_5$]