A bob is hanging over a pulley inside a car through, a string. Th… - Vidyadip

MCQ

A bob is hanging over a pulley inside a car through, a string. The second end of the string is in the hand of a person standing in the car. The car is moving with constant acceleration ' $a$ ' directed horizontally as shown in figure. Other end of the string is pulled with constant acceleration ' $a$ ' vertically. The tension in the string is equal to-

A
$m \sqrt{g^2+a^2}$
B
$m \sqrt{ g ^2+ a ^2}- ma$
✓
$m \sqrt{g^2+a^2}+m a$
D
$m ( g + a )$

✓

Answer

Correct option: C.

$m \sqrt{g^2+a^2}+m a$

c
(c)

Applying Newton's law along string

$\Rightarrow T - m \sqrt{ g ^2+ a ^2}= ma$

$\text { or } T = m \sqrt{ g ^2+ a ^2}+ ma$

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