MCQ
A body, acted upon by a force of $50 \,N$ is displaced through a distance $10$ meter in a direction making an angle of $60^°$ with the force. The work done by the force be ..........$J$
  • A
    $200$
  • B
    $100$
  • C
    $300$
  • $250$

Answer

Correct option: D.
$250$
d
(d) $W = \overrightarrow F \,.\,\overrightarrow S = FS\cos \theta $

$ = 50 \times 10 \times \cos 60^\circ = 50 \times 10 \times \frac{1}{2} = 250\,J.$

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