MCQ
A body cools from ${50.0^o}C$ to ${49.9^o}C$ in $5\;s$. How long will it take to cool from ${40.0^o}C$ to ${39.9^o}C$? Assume the temperature of surroundings to be ${30.0^o}C$ and Newton's law of cooling to be valid ....... $\sec$
  • A
    $2.5 $
  • $10 $
  • C
    $20$
  • D
    $5$

Answer

Correct option: B.
$10 $
b
(b) $\frac{{50 - 49.9}}{5} = K\,\left( {\frac{{50 + 49.9}}{2} - 30} \right)$…..$(i)$
$\frac{{40 - 39.9}}{t} = K\,\left[ {\frac{{40 + 39.9}}{2} - 30} \right]$…..$(ii)$
from equations $(i)$ and $(ii)$

we get $t ≈ 10 sec$ .

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