MCQ
A body is executing simple harmonic motion with an angular frequency $2\ rad / s$. The velocity of the body at $20\ mm$ displacement, when the amplitude of motion is $60 \ mm$, is
- A$40\ mm / s$
- B$60\ mm / s$
- ✓$113\ mm / s$
- D$120\ mm / s$
✓
Answer
Correct option: C.
$113\ mm / s$
(c) $\quad v=\omega \sqrt{\left(a^2-y^2\right)}=2 \sqrt{60^2-20^2}=113 \mathrm{~mm} / \mathrm{s}$.
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