MCQ
A body is executing simple harmonic motion with an angular frequency $2\,rad/s$. The velocity of the body at $20\, mm$ displacement, when the amplitude of motion is $60\, mm$, is ...... $mm/s$
- A$40$
- B$60$
- ✓$113$
- D$120$
✓
Answer
Correct option: C.
$113$
c
(c) $v = \omega \sqrt {({a^2} - {y^2})} = 2\sqrt {{{60}^2} - {{20}^2}} = 113\,mm/s$.
(c) $v = \omega \sqrt {({a^2} - {y^2})} = 2\sqrt {{{60}^2} - {{20}^2}} = 113\,mm/s$.
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