MCQ
A body is projected vertically up with a speed $v_0$ in gravity. The average speed of the body over a time $\frac{v_0}{g}$ calculated from the instant of projection is
- A$v_0$
- Bzero
- C$\frac{2v_0}{3}$
- ✓$\frac{v_0}{2}$
✓
Answer
Correct option: D.
$\frac{v_0}{2}$
d
Average velocity $=0$ because net displacement of the body is zero.
Average velocity $=0$ because net displacement of the body is zero.
Average speed $=\frac{\text { Total distance covered }}{\text { Time of flight }}$ $=\frac{2 H_{\max }}{2 u / g}$
$\Rightarrow v_{a v}=\frac{2 u^{2} / 2 g}{2 u / g} \Rightarrow v_{a v}=\frac{u}{2}$
Velocity of projection $=\mathrm{v}$ (given)
$\therefore v_{a v}=\frac{v}{2}$
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