A body of mass $0.01 kg$ executes simple harmonic motion $(S.H.M.)$ about $x = 0$ under the influence of a force shown below : The period of the $S.H.M.$ is .... $s$
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(d) From graph, slope $K = \frac{F}{x} = \frac{8}{2} = 4$
$T = 2\pi \sqrt {\frac{m}{K}} \Rightarrow T = 2\pi \sqrt {\frac{{0.01}}{4}} = 0.3\sec $
$T = 2\pi \sqrt {\frac{m}{K}} \Rightarrow T = 2\pi \sqrt {\frac{{0.01}}{4}} = 0.3\sec $
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