- A$2$
- B$(2 \times g)$
- C$(4 \times g)$
- ✓$4$
$R = m(g + a) = 2(g + g) = 4g\;N = 4\;kg$ [As $a = g$]
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If two springs $S_1$ and $S_2$ of force constants $k_1$ and $k_2$, respectively, are stretched by the same force, it is found that more work is done on spring $S_1$ than on spring $S_2$.
Statement $-1$: If stretched by the same amount, work done on $S_1$, will be more than that on $S_2$
Statement $-2$ : $k_1 < k_2$.

Process $-1$:An amount of thermal energy $Q$ is added to the material and $\frac{2}{3}$ of the material melts.
Process $-2$:An identical additional amountof thermal energy $Q$ is added to the materlal is now a liquid at $4\,^o C$
........ $^oC$ is the ratio of the latent heat of fusion to the specific heat of the liquid for this material.