MCQ
A body performing unifom circular motion completed $140$ revolution in a second. Its angular speed is .......... $rad / s$
- ✓$880$
- B$440$
- C$220$
- D$240$
$f=140 red / sec$
$\omega=2 \pi F \rightarrow$ frequency
$\downarrow$
angular speed
$\omega=2 \pi x 140$.
$\omega=280 \times 3.14=879.8 rad / s$
$\omega \simeq 880 rad / s$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
