MCQ
A body starts from rest from the origin with an acceleration of $6 \;m / s^2$ along the $x$-axis and $8\; m / s^2$ along the $y$-axis. Its distance from the origin after $4\; seconds$ will be
- A$56 $
- B$64$
- ✓$80$
- D$128 $
✓
Answer
Correct option: C.
$80$
c
$x = {u_x}t + \frac{1}{2}{a_x}{t^2} = \frac{1}{2} \times 6 \times {(4)^2} = 48\,m$
$x = {u_x}t + \frac{1}{2}{a_x}{t^2} = \frac{1}{2} \times 6 \times {(4)^2} = 48\,m$
$y = {u_y}t + \frac{1}{2}{a_y}{t^2} = \frac{1}{2} \times 8 \times {(4)^2} = 64\,m$
$d = \sqrt {{x^2} + {y^2}} = \sqrt {{{(48)}^2} + {{(64)}^2}} = 80\,m$
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