MCQ
A body, thrown upwards with some velocity, reaches the maximum height of $20\,m$. Another body with double the mass thrown up, with double initial velocity will reach a maximum height of..........$m$
- A$200$
- B$16$
- ✓$80$
- D$40$
$H = \frac{{{u^2}}}{{2g}} \Rightarrow H \propto {u^2}$,
So if velocity is doubled then height will become four times. i.e. $H = 20 \times 4 = 80\,m$
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