MCQ
A bomb is projected upwards. At topmost point it explodes in three identical fragments. First fragment comes to ground in $10\  sec$. and others in $20\  sec$ each. Then the height reached by the original bomb is.........$m$
  • A
    $800$
  • B
    $1600$
  • $1250$
  • D
    $1500$

Answer

Correct option: C.
$1250$
c
$h=v(10)+\frac{1}{2} g(10)^{2}$

$\mathrm{h}=-\frac{\mathrm{V}}{2}(20)+\frac{1}{2} \mathrm{g}(20)^{2}$

adding we get $\mathrm{h}=1250 \mathrm{m}$

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