MCQ
A buffer solution contains $1\ mole$ of ammonium sulphate and $1\ mole$ of $NH_4OH$ ($K_b = 10^{-5}$). The $pH$ of solution will be
- A$5$
- B$9$
- C$5.3$
- ✓$8.7$
$\left[\mathrm{NH}_{4}^{+}\right]=2 \times$ mole of $\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}$
$\therefore \mathrm{pOH}=5+\log 2=5.3$
or $\mathrm{pH}=8.7$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$H _2 O ( g ) \rightarrow H _2( g )+\frac{1}{2} O _2( g )$
The percent of water decomposing at $2300\,K$ and $1\,bar$ is $...........$ (Nearest integer).
Equilibrium constant for the reaction is $2 \times 10^{-3}$ at $2300\,K$
