MCQ
A buffer solution contains $1\  mole$ of ammonium sulphate and $1\  mole$ of $NH_4OH$ ($K_b = 10^{-5}$). The $pH$ of solution will be
  • A
    $5$
  • B
    $9$
  • C
    $5.3$
  • $8.7$

Answer

Correct option: D.
$8.7$
d
$\mathrm{pOH}=\mathrm{pK}_{\mathrm{b}}+\log \frac{[\mathrm{Salt}]}{[\mathrm{Base}]}=\mathrm{pK}_{\mathrm{b}}+\log \frac{[\mathrm{Cation}]}{[\mathrm{Base}]}$

$\left[\mathrm{NH}_{4}^{+}\right]=2 \times$ mole of $\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}$

$\therefore \mathrm{pOH}=5+\log 2=5.3$

or $\mathrm{pH}=8.7$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free