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Calorimetry — Physics STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 SciencePhysicsCalorimetry1 Mark
Question
A bullet of mass 20g enters into a fixed wooden block with a speed of $40ms^{-1}$ and stops in it. Find the change in internal energy during the process.
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Answer

Given, Mass of bullet, m = 20g = 0.02kg Initial velocity of the bullet, $u = 40ms^{-1}$ Final velocity of the bullet = $0ms^{-1}​​​​​​​$ Initial kinetic energy of the bullet $=\frac{1}{2}\text{mu}^2$$=\frac{1}{2}\times0.02\times40\times40=16\text{J}$
Final kinetic energy of the bullet = 0 Change in energy of the bullet = 16J It is given that the bullet enters the block and stops inside it. The total change in its kinetic energy is responsible for the change in the internal energy of the block.$\therefore$ Change in internal energy of the block = Change in energy of the bullet = 16J.

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