MCQ
A capacitor having capacitance $C$ is charged to a voltage $V$. It is then removed and connected in parallel with another identical capacitor which is uncharged. The new charge on each capacitor is now
- A$CV$
- ✓$CV / 2$
- C$2 CV$
- D$CV / 4$
✓
Answer
Correct option: B.
$CV / 2$
b
(b) Charge flows to second capacitor until the potential is same i.e. $V/2$. So new charge = $CV/ 2$
(b) Charge flows to second capacitor until the potential is same i.e. $V/2$. So new charge = $CV/ 2$
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