MCQ
A capacitor is charged by using a battery which is then disconnected. A dielectric slab is introduced between the plates which results in:
  • A
    Increase in the potential difference across the plates and reduction in stored energy but no change in the charge on the plates.
  • Decrease in the potential difference across the plates and reduction in the stored energy but no change in the charge on the plates.
  • C
    Reduction of charge on the plates and Increase of potential difference across the plates.
  • D
    Increase in stored energy but no change in potential difference across the plates.

Answer

Correct option: B.
Decrease in the potential difference across the plates and reduction in the stored energy but no change in the charge on the plates.

If a dielectric slab of dielectric constant K is filled in between the plates of a capacitor after charging the capacitor $($i.e., after removing the connection of battery with the plates of capacitor$)$ the potential difference between the plates reduces to $\frac{1}{\text{K}}$​ times and the potential energy of capacitor reduces to$\frac{1}{\text{K}}$times but there is no change in the charge on the plates.

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