MCQ
A capacitor is connected to an $A.C.$ circuit, then the phase difference between current and the voltage is:
- A$\pi$
- ✓$\frac{\pi}{2}$
- C$\frac{-\pi}{2}$
- D$\text{Zero}$
✓
Answer
Correct option: B.
$\frac{\pi}{2}$
Current leads voltage by $\frac{\pi}{2}$
$\therefore$ phase difference is $=\frac{\pi}{2}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
There are two electric bulbs of 40 W and 100 W. Which one will be brighter when first connected in series and then in parallel,
Which of the following shown particle nature of light
The unit of focal power of a lens is
Out of the following, waves of which frequency can penetrate ionosphere?
Magnetic dipole moment is a vector quantity directed from:
In Young's experiment, monochromatic light is used to illuminate the two slits $A$ and $B.$ interference fringes are observed on a screen placed infront of the slits. Now if a thin glass plate is placed normally in the path of the beam coming from the slit $A$, then
→In the given figure, if the Wheatstone bridge is in balanced condition, then the value of resistance 'S' will be
The following diagram indicates the energy levels of a certain atom when the system moves from 2E level to E, a photon of wavelength $\lambda $ is emitted. The wavelength of photon produced during its transition from $\frac{{4E}}{3}$ level to E is
→An electric dipole is situated in an electric field of uniform intensity $E$ whose dipole moment is $p$ and moment of inertia is $I$. If the dipole is displaced slightly from the equilibrium position, then the angular frequency of its oscillations is
→An electric dipole is placed in an electric field generated by a point charge