A capacitor is made of two square plates each of side $a$ making a very small angle $\alpha$ between them, as shown in figure. The capacitance will be close to
  • A$\frac{\varepsilon_{0} a^{2}}{d}\left(1-\frac{3 \alpha a}{2 d}\right)$
  • B$\frac{\varepsilon_{0} a^{2}}{d}\left(1-\frac{\alpha a}{4 d}\right)$
  • C$\frac{\varepsilon_{0} {a}^{2}}{\mathrm{d}}\left(1+\frac{\alpha {a}}{\mathrm{d}}\right)$
  • D$\frac{\varepsilon_{0} a^{2}}{d}\left(1-\frac{\alpha a}{2 d}\right)$
JEE MAIN 2020, Diffcult
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