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Capacitors — Physics STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 SciencePhysicsCapacitors1 Mark
Question
A capacitor with stored energy 4.0J is connected with an identical capacitor with no electric field in between. Find the total energy stored in the two capacitors.
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Answer

Stored energy of capacitor $C_1= 4.0J$
$=\frac{1}{2}\frac{\text{q}^2}{\text{c}^2}=4.0\text{J}$
When then connected, the charge shared
$=\frac{1}{2}\frac{\text{q}^2_1}{\text{c}^2}=\frac{1}{2}\frac{\text{q}^2_2}{\text{c}^2}$
$\Rightarrow\text{q}_1=\text{q}_2$
So, that the energy should divided.
$\therefore$ The total energy stored in the two capacitors each is 2J.

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