MCQ
A car is moving at a speed of $40\,m/s$ on a circular track of radius $400\,m.$ This speed is increasing at the rate of $3\,m/s^2.$ The acceleration of car is ........ $m/s^2$
- A$4$
- B$7$
- ✓$5$
- D$3$
✓
Answer
Correct option: C.
$5$
c
$a_{t}=3 \mathrm{m} / \mathrm{s}^{2}$
$a_{t}=3 \mathrm{m} / \mathrm{s}^{2}$
$a_{c}=\frac{v^{2}}{r}=\frac{1600}{400}=4$
$a=\sqrt{a_{c}^{2}+a_{t}^{2}}=5 \mathrm{m} / \mathrm{s}^{2}$
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