A cell whose e.m.f. is $2\, V$ and internal resistance is $0.1\,\Omega $, is connected with a resistance of $3.9\,\Omega $. The voltage across the cell terminal will be ................ $V$
AIIMS 2001,AIPMT 1999, Medium
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The voltage across cell terminal will be given by
$ = \frac{E}{{R + r}} \times R$ $ = \frac{2}{{(3.9 + 0.1)}} \times 3.9 = 1.95\,V$
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