Question
A charged particle moves through a magnetic field perpendicular to its direction. Then
✓
Answer
When a charged particle enters a magnetic field at a direction perpendicular to the direction of motion, the path of the motion is circular. In circular motion the direction of velocity changes at every point (the magnitude remains constant). Therefore, the tangential momentum will change at every point. But kinetic energy will remain constant as it is given by $\frac{1}{2}mv^2$ and $v^2$ is the square of the magnitude of velocity which does not change.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
If the temperature of the atmosphere is increased the following character of the sound wave is effected
The number of molecules in one litre of an ideal gas at $300 \,{K}$ and $2$ atmospheric pressure with mean kinetic energy $2 \times 10^{-9}\, {J}$ per molecules is $....\, \times 10^{11}$
→Find magnetic field at centre $P$ if length of side of square loop is $20\, cm$
→If a car at rest accelerates uniformly to a speed of $144 \,km/h$ in $20 \,s$. Then it covers a distance of........$m$
→$A$ ray incident at an angle $53^o$ on a prism emerges at an angle at $37^o$ as shown. If the angle of incidence is made $50^o$, which of the following is a possible value of the angle of emergence......$^o$
→A common emitter amplifier circuit is shown in the figure below. For the transistor used in the circuit the current amplification factor, ${\beta _{dc}} = 100$. Other parameters are mentioned in the figure.
→The velocity of a particle moving in the positive direction of $x$-axis varies as $v=5 \sqrt{x}$. Assuming that at $t=0$, particle was at $x=0$. What is the acceleration of the particle $.........m/s^2$
→Light of wavelength $2475\, Å$ is incident on barium. Photoelectrons emitted describe a circle of radius $100\, cm$ by a magnetic field of flux density $\frac{1}{{\sqrt {17} }} \times {10^{ - 5}}$ $Tesla$. Work function of the barium is .............. $eV$ (Given $\frac{e}{m} = 1.7 \times {10^{11}})$
→The fine powder of a coloured glass is seen as
What percentage of original radioactive atoms is left after five half lives..........$\%$
→