A closely wound flat circular coil of $25$ $turns$ of wire has diameter of $10\, cm$ and carries a current of $4\, ampere$. Determine the flux density at the centre of a coil
AIIMS 2001, Easy
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(c) $B = {10^{ - 7}}\frac{{2\pi ni}}{r} = {10^{ - 7}} \times \frac{{2 \times \pi \times 25 \times 4}}{{5 \times {{10}^{ - 2}}}} = 1.257 \times {10^{ - 3}}\,T$
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