Question
A coin is tossed two times. Find the probability of getting at most one head.

Answer

The possible outcomes, if a coin is tossed 2 times is,
S = {(HH), (TT), (HT), (TH)}
$\therefore$ n(S) = 4
Let E = Event of getting atmost one head
= {(TT), (HT), (TH)}
$\therefore$ n(E) = 3
Hence, required probability $=\frac{\text{n(E)}}{\text{n(S)}}=\frac{3}{4}$

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