- A$K_2[Pt\, Cl_4]$
- ✓$K_2[Pt\, Cl_6]$
- C$K_3[Pt\, Cl_5]$
- D$K[Pt\, Cl_3]$
(2) $K _{2} P t Cl _{6} \rightarrow 2 K ^{+}+\left[ P _{ t } Cl _{6}\right]^{2-} ; i =1+2=3$
In $(1)$, oxidation number of $Pt =2$
In $(2),$ the oxidation number of $P t=4$
Therefore, $K _{2}\left[ P t Cl _{6}\right]$ is the correct answer.
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$(A)$ the reaction of $Al _2 O _3$ with coke ($C$) at a temperature $>2500^{\circ} C$.
$(B)$ the neutralization of aluminate solution by passing $CO _2$ gas to precipitate hydrated alumina $\left( Al _2 O _3 .3 H _2 O \right)$
$(C)$ the dissolution of $Al _2 O _3$ in hot aqueous $NaOH$.
$(D)$ the electrolysis of $Al _2 O _3$ mixed with $Na _3 AlF _6$ to give $Al$ and $CO _2$.

$(A)$ Graphite is harder than diamond.
$(B)$ Graphite has higher electrical conductivity than diamond
$(C)$ Graphite has higher thermal conductivity than diamond
$(D)$ Graphite has higher $C$ - $C$ bond order than diamond