MCQ
A complex has a composition corresponding to the formula $CoBr_2Cl\cdot 4NH_3$ . What is the structural formula if conductance measurements show two ions per formula unit ? Silver nitrate solution given an immediate precipitate of $AgCl$ but no $AgBr$
  • A
    $[CoBrCl(NH_3)_4]Br$
  • B
    $[CoCl(NH_3)_4]Br_2$
  • C
    $[CoBr_2Cl(NH_3)_4]$
  • $[CoBr_2(NH_3)_4]Cl$

Answer

Correct option: D.
$[CoBr_2(NH_3)_4]Cl$
d
since a precipitate of AgCl is obtained on treatment with silver nitrate, but no precipitate of AgBr, is obtained, chlorine is present in the ionization sphere and bromine is present in the coordination sphere.

Since conductance measurements show two ions per formula unit, all the ammonia ligands are present in the coordination sphere. Hence, the structural formula is $\left[ CoBr _{2}\left( NH _{3}\right)_{4}\right] Cl$

$ {\left[ CoBr _{2}\left( NH _{3}\right)_{4}\right] Cl + AgNO _{3} \rightleftharpoons\left[ CoBr _{2}\left( NH _{3}\right)_{4}\right]+ NO _{3}^{-}+ AgCl }$

${\left[ CoBr _{2}\left( NH _{3}\right)_{4}\right] Cl\rightleftharpoons\left[ CoBr _{2}\left( NH _{3}\right)_{4}\right]+Cl ^{-}}$

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