A composite parallel plate capacitor is made up of two different dielectric materials with different thickness $\left(t_{1}\right.$ and $\left.t_{2}\right)$ as shown in figure. The two different dielectric material are separated by a conducting foil $F$. The voltage of the conducting foil is $.....V$
JEE MAIN 2022, Diffcult
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Capacitance of each capacitor
$C _{1}=\frac{ A 3 \epsilon_{0}}{\frac{1}{2}}=6 A \epsilon_{0}$
$C _{2}= A 4 E _{0}=4 A \in_{0}$
Equivalent capacitance
$C _{\text {eq }}=\frac{ C _{1} C _{2}}{ C _{1}+ C _{2}} \Rightarrow \frac{24}{10} A \in_{0}$
$q _{\text {net }}= C _{\text {eq }}(\Delta V ) \Rightarrow 240 A \in_{0}$
$\Delta V _{2}=\frac{240 A \epsilon_{0}}{4 A \epsilon_{0}}=60\,V$
$\left(\Delta V _{2}=\text { Potential drop across } C _{2}\right)$
$V _{\text {foil }}=60\,V$
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