Question
A compound contains $2.8\%$ $Fe$ by mass. If the compound contains single $Fe$ atom in its one molecule, then the molar mass $(g/mol)$ of the compound is $(Fe = 56\, amu)$
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Answer
Let's do this by the unitary method.
$2.8 \%$ of the molecular mass $=56$ $u$
$1 \%$ of the molecular mass $=\frac{56}{2.8} \mathrm{u}$
$100 \%$ of the molecular mass $=100 \times \frac{56}{2.8} \mathrm{u}=2.0 \times 10^{3} \mathrm{u}$ or $2000 \mathrm{u}$
If the mass of one molecule is $2000$ $u$, the mass of one mole is $2000$ $g$.
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