MCQ
A compound contains $69.5\%$ oxygen, $30.5\%$ nitrogen and its molecular weight is $92$. The formula of compound is :
- A$\ce{N_2O}$
- B$\ce{NO_2}$
- ✓$\ce{N_2O_4}$
- D$\ce{N_2O_5}$
✓
Answer
Correct option: C.
$\ce{N_2O_4}$
| Element | $\%$ | $\%$ at. wt | Ratio |
| $N$ | $30.5$ | $\frac{30.5}{14}=2.18$ | $1$ |
| $O$ | $69.5$ | $\frac{69.5}{16}=4.34$ | $2$ |
Empirical formula weight $= 46$
$\text{n} = \frac{92}{46} = 2$
$\Rightarrow $ Molecular formula $= \ce{(NO_2)_2 = N_2O_4}$
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