MCQ
A compound does not react with $2,4$ di-nitrophenyl hydrazine and $Na$ , compound is
- AAcetone
- BAcetaldehyde
- C$C{H_3}OH$
- ✓$C{H_2} = CHOC{H_3}$
It is not $C{H_3}OH$ as does not react with $Na$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| List-$I$ (Compound) | List-$II$ (Colour) |
| $A$ $\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3 \cdot \mathrm{xH}_2 \mathrm{O}$ | $I$ Violet |
| $B$ $\left[\mathrm{Fe}(\mathrm{CN})_5 \mathrm{NOS}\right]^{4-}$ | $II$ Blood Red |
| $C$ $[\mathrm{Fe}(\mathrm{SCN})]^{2+}$ | $III$ Prussian Blue |
| $D$ $\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4 \cdot 12 \mathrm{MoO}_3$ | $IV$ Yellow |
Choose the correct answer from the options given below :
$\begin{array}{*{20}{c}}
{{{\left( {{C_2}{H_5}} \right)}_2}NC{H_2}CH \cdot COOH} \\
{\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,Cl}
\end{array}$
is :