Question
A compound formed by elements $A$ and $B$ has a cubic structure in which $A$ atoms are at the corners of the cube and $B$ atoms are at the face centres. Derive the formula of the compound.

Answer

Number of $A$ atoms per unit cell $= 8($at the corners$) \times\frac{1}{8}=1$
Number of $B$ atoms per unit cell $= 6($at the centres$) \times\frac{1}{2}=3$
$A : = 1 : 3$
$\therefore$ The formula of the compound $= AB_3.$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free