Question
A compound forms hexagonal close-packed structure. What is the total number of voids in 0.5 mol of it? How many of these are tetrahedral voids?

Answer

$\text { Number of closed packed particles }=0.5 \times 6.022 \times 10^{23}=3.011 \times 10^{23} 0.5 \times 6.022 \times 1023=3.011 \times 1023 \text { Therefore }$
$\text { number of octhahedral voids }=3.011 \times 10^{23} \times 1023$
$\text { and number of tetrahedral voids }=2 \times 3.011 \times 10^{23}=6.022 \times 10^{23} 2 \times 3.011 \times 1023=6.022 \times 1023 \text { Therefore total }$
$\text { number of voids }=3.011 \times 10^{23}+6.022 \times 10^{23}=9.033 \times 10^{23} 3.011 \times 1023+6.022 \times 1023=9.033 \times 1023$

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