MCQ
A compound of carbon hydrogen and nitrogen contains three elements in the respective ratio of $9 : 1 : 35$ grams. The Empirical formula for the compound is
- A${C_2}{H_4}N$
- ✓${C_3}{H_4}N$
- C${C_3}{H_6}N$
- D${C_2}{H_6}N$
Molar ratio of $C: H: N=\frac{9}{12}: \frac{1}{1}: \frac{3.5}{14}=0.75: 1: 0.25$
$=\frac{0.75}{0.25}: \frac{1}{0.25}: \frac{0.25}{0.25}$
$=3: 4: 1$
Thesefore, the empirical formula is $C _3 H _4 N$
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