Question
A conducting rod $10 cm$ long is being pulled along horizontal, frictionless conducting rails at a con-stant $5 m / s$. The rails are shorted at one end with a metal strip. There is a uniform magnetic field of strength $1.2 T$ out of the page in the region in which the rod moves. If the resistance of the rod is $0.5 \Omega$, what is the power of the external agent pulling the rod?
Assume that the resistance of the rails is negligibly small.

Answer

Data: $I=0.1 m , B=1.2 T , v =5 m / s \cdot R=0.5 \Omega$
Power, $P =\frac{(B l v)^2}{R}=\frac{(1.2 \times 0.1 \times 5)^2}{0.5}=0.72 W$

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