MCQ
A conductivity cell containing $0.001 \mathrm{M} \mathrm{AgNO}_3$ solution develops resistance $6530 \mathrm{ohm}$ at $25^{\circ} \mathrm{C}$. Calculate the electrical conductivity of solution at same temperature if the cell constant is $0.653 \mathrm{~cm}^{-1}$.

Answer

Correct option: D.
$1.0 \times 10^{-4} \Omega^{-1} cm ^{-1}$
(d) : $kappa =\frac{\text { Cell constant }}{\text { Resistance }}=\frac{0.653}{6530}=1.0 \times 10^{-4} \Omega^{-1} cm ^{-1}$

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