A conductor $ABCDE$, shaped as shown, carries a current i. It is placed in the $xy$ plane with the ends $A$ and $E$ on the $x$-axis. $A$ uniform magnetic field of magnitude $B$ exists in the region. The force acting on it will be
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To find the Ampere's force on a conductor of any shape, replace the conductor by an imagninary straight conductor joining the two ends of the given conductor. So, if $\mathrm{B}$ is in $\mathrm{x}$ $-direction,$ then the imaginary staright conductor will be along the field and the force acting on it will be zero. If $B$ is in $y$ direction, then the force will be $\lambda B I$ acting along the $\mathrm{x}$ direction. Similarly, if $\mathrm{B}$ is in the $z$ direction, then the force will be $\lambda B I$, acting along the negative $y$ direction.
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