MCQ
A constant force acting on a body of mass of $5\,kg$ changes its speed from $5\,ms^{-1}$ to $10\,ms^{-1}$ in $10\,s$ without changing the direction of motion. The force acting on the body is ......... $N$
- A$1.5$
- B$2$
- ✓$2.5$
- D$5$
✓
Answer
Correct option: C.
$2.5$
c
$a=\frac{v-u}{t}=\frac{(10-5) m s^{-1}}{10 s}=0.5 \mathrm{ms}^{-2}$
$a=\frac{v-u}{t}=\frac{(10-5) m s^{-1}}{10 s}=0.5 \mathrm{ms}^{-2}$
As $\mathrm{F}=\mathrm{ma}$
$\therefore \mathrm{F}=(5 \mathrm{kg})\left(0.5 \mathrm{ms}^{-2}\right)=2.5 \mathrm{N}$
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