A constant voltage is applied between the two ends of a uniform metallic wire. Some heat is developed in it. The heat developed is double if
AIIMS 2012, Medium
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$R=\frac{\rho \ell}{\pi r^{2}}$

When $\ell$ is $\frac{\ell}{2}$ and radius is $\frac{\mathrm{r}}{2}$

$\therefore \quad \mathrm{R}^{\prime}=\frac{\rho \ell{4}}{\pi 2 \mathrm{r}^{2}}=\frac{2 \rho \ell}{\pi \mathrm{r}^{2}}$

So, $\mathrm{R}^{\prime}=2 \mathrm{R}$ So, heat is doubled according to $\mathrm{H}=\mathrm{I}^{2} \mathrm{RT}$

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